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0=(x+3)(x+4)(x-4)
We move all terms to the left:
0-((x+3)(x+4)(x-4))=0
We add all the numbers together, and all the variables
-((x+3)(x+4)(x-4))=0
We multiply parentheses ..
-((+x^2+4x+3x+12)(x-4))=0
We calculate terms in parentheses: -((+x^2+4x+3x+12)(x-4)), so:
(+x^2+4x+3x+12)(x-4)
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(+x^2+4x+3x+12)(x-4)
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(+x^2+4x+3x+12)(x-4)
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(+x^2+4x+3x+12)(x-4)
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(+x^2+4x+3x+12)(x-4)
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(+x^2+4x+3x+12)(x-4)
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