0=-0.5d2+8d

Solution for 0=-0.5d2+8d equation:

0=-0.5d^2+8d

We move all terms to the left:

0-(-0.5d^2+8d)=0

We add all the numbers together, and all the variables

-(-0.5d^2+8d)=0

We get rid of parentheses

0.5d^2-8d=0

a = 0.5; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·0.5·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*0.5}=\frac{0}{1}
=0
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*0.5}=\frac{16}{1}
=16
$