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0=-1/3(x-5)(x+5)
We move all terms to the left:
0-(-1/3(x-5)(x+5))=0
Domain of the equation: 3(x-5)(x+5))!=0We add all the numbers together, and all the variables
x∈R
-(-1/3(x-5)(x+5))=0
We use the square of the difference formula
x^2+25=0
a = 1; b = 0; c = +25;
Δ = b2-4ac
Δ = 02-4·1·25
Δ = -100
Delta is less than zero, so there is no solution for the equation
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