0=-16t2+10t+6

Solution for 0=-16t2+10t+6 equation:

0=-16t^2+10t+6

We move all terms to the left:

0-(-16t^2+10t+6)=0

We add all the numbers together, and all the variables

-(-16t^2+10t+6)=0

We get rid of parentheses

16t^2-10t-6=0

a = 16; b = -10; c = -6;
Δ = b2-4ac
Δ = -102-4·16·(-6)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-22}{2*16}=\frac{-12}{32}
=-3/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+22}{2*16}=\frac{32}{32}
=1
$