0=-16t2+1444

Solution for 0=-16t2+1444 equation:

0=-16t^2+1444

We move all terms to the left:

0-(-16t^2+1444)=0

We add all the numbers together, and all the variables

-(-16t^2+1444)=0

We get rid of parentheses

16t^2-1444=0

a = 16; b = 0; c = -1444;
Δ = b2-4ac
Δ = 02-4·16·(-1444)
Δ = 92416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{92416}=304$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-304}{2*16}=\frac{-304}{32}
=-9+1/2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+304}{2*16}=\frac{304}{32}
=9+1/2
$