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0=-16t^2+20t
We move all terms to the left:
0-(-16t^2+20t)=0
We add all the numbers together, and all the variables
-(-16t^2+20t)=0
We get rid of parentheses
16t^2-20t=0
a = 16; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·16·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:t_{1}=\frac{-b-\sqrt{\Delta}}{2a}t_{2}=\frac{-b+\sqrt{\Delta}}{2a}\sqrt{\Delta}=\sqrt{400}=20t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*16}=\frac{0}{32} =0t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*16}=\frac{40}{32} =1+1/4
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