0=-16t2+70t

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Solution for 0=-16t2+70t equation:



0=-16t^2+70t
We move all terms to the left:
0-(-16t^2+70t)=0
We add all the numbers together, and all the variables
-(-16t^2+70t)=0
We get rid of parentheses
16t^2-70t=0
a = 16; b = -70; c = 0;
Δ = b2-4ac
Δ = -702-4·16·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-70}{2*16}=\frac{0}{32} =0 $
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+70}{2*16}=\frac{140}{32} =4+3/8 $

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