If it's not what You are looking for type in the equation solver your own equation and let us solve it.
0=-16x^2+32x+5
We move all terms to the left:
0-(-16x^2+32x+5)=0
We add all the numbers together, and all the variables
-(-16x^2+32x+5)=0
We get rid of parentheses
16x^2-32x-5=0
a = 16; b = -32; c = -5;
Δ = b2-4ac
Δ = -322-4·16·(-5)
Δ = 1344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1344}=\sqrt{64*21}=\sqrt{64}*\sqrt{21}=8\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-8\sqrt{21}}{2*16}=\frac{32-8\sqrt{21}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+8\sqrt{21}}{2*16}=\frac{32+8\sqrt{21}}{32} $
| 22x-7=12x-27 | | R-6+7=-9-4R+7r | | 2x+9=3*2+x | | 5m=9=19 | | 17=-7z+3= | | a^2+15a+26=0 | | -12=4(x-8) | | 3x+7=4x-(3+2x) | | 2a+a=7 | | N-1=13+5n | | -7n-4=2(n-8) | | 3/2a-4/3a=-10/3+8/3a | | 5(2x-4)=3(2x+1)-1 | | (4x+2)-(2x+1)=6 | | 3x-40°=x+30 | | 45/x=9/3 | | 4a=8/5 | | 5x-18=-43 | | 10n+27=7n+14 | | -5(x-8)=-45 | | 2b+11=4b+3 | | x+8=13-6x | | -5(3x-8)=-45= | | 2x+10=-x+1 | | x+12+x=180 | | 1/3(m+21)+2/3m=2 | | 3x-20=55. | | 2x^2+10+12x=0 | | -6x²+30x+84=0 | | x2-6x=10+3x | | 5/7x=84 | | 6x+19=2x+55 |