If it's not what You are looking for type in the equation solver your own equation and let us solve it.
0=-16x^2+4013x+3250
We move all terms to the left:
0-(-16x^2+4013x+3250)=0
We add all the numbers together, and all the variables
-(-16x^2+4013x+3250)=0
We get rid of parentheses
16x^2-4013x-3250=0
a = 16; b = -4013; c = -3250;
Δ = b2-4ac
Δ = -40132-4·16·(-3250)
Δ = 16312169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4013)-\sqrt{16312169}}{2*16}=\frac{4013-\sqrt{16312169}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4013)+\sqrt{16312169}}{2*16}=\frac{4013+\sqrt{16312169}}{32} $
| x+4+3=1 | | 32=2x+5x+4 | | 30x^2-150x=180 | | 53=-6x+x+8 | | g-11=23 | | v/4+13=34 | | 9x+10-x=26 | | P=2(4x^2-3x)+2(7x-2) | | –3k+7−3k=5−4k | | –3x–7=20 | | -b+5+5=2 | | -7)+x=(-15 | | 3x+87=5x-3 | | 294=(30x)(14) | | (5-2v)=-4(3v+1) | | -1.2+u/7=18.7 | | 43-5x7=43-35 | | 6•10^2x=48 | | 3×y-1=17 | | 3x+2x^2=2 | | x/20+5=50 | | 3=3e÷4e+7+2 | | 5+3(y+-4)=5(y+2)+-1y | | 4x+18=10x+12x | | 3(5x-1=138 | | 3-x=-2x+1 | | 6x+28=2(x+20) | | (4-7x)-3=15 | | 3(4-2t)15= | | 27=r+7 | | -5/6=-1/5v-2/3 | | 10-x=0.50(x-1) |