0=-16x2+672

Solution for 0=-16x2+672 equation:

0=-16x^2+672

We move all terms to the left:

0-(-16x^2+672)=0

We add all the numbers together, and all the variables

-(-16x^2+672)=0

We get rid of parentheses

16x^2-672=0

a = 16; b = 0; c = -672;
Δ = b2-4ac
Δ = 02-4·16·(-672)
Δ = 43008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{43008}=\sqrt{1024*42}=\sqrt{1024}*\sqrt{42}=32\sqrt{42}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{42}}{2*16}=\frac{0-32\sqrt{42}}{32}
=-\frac{32\sqrt{42}}{32}
=-\sqrt{42}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{42}}{2*16}=\frac{0+32\sqrt{42}}{32}
=\frac{32\sqrt{42}}{32}
=\sqrt{42}
$