0=-2(1+6b)+6(4+2b)

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Solution for 0=-2(1+6b)+6(4+2b) equation: 



0=-2(1+6b)+6(4+2b)

We move all terms to the left:

0-(-2(1+6b)+6(4+2b))=0

We add all the numbers together, and all the variables

-(-2(6b+1)+6(2b+4))+0=0

We add all the numbers together, and all the variables

-(-2(6b+1)+6(2b+4))=0



We calculate terms in parentheses: -(-2(6b+1)+6(2b+4)), so:

-2(6b+1)+6(2b+4)

We multiply parentheses

-12b+12b-2+24

We add all the numbers together, and all the variables

22

Back to the equation:

-(22)



We move all terms containing b to the left, all other terms to the right

=22

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