0=-2(u+-1)u=

Solution for 0=-2(u+-1)u= equation:

0=-2(u+-1)u=

We move all terms to the left:

0-(-2(u+-1)u)=0

We add all the numbers together, and all the variables

-(-2(u-1)u)+0=0

We add all the numbers together, and all the variables

-(-2(u-1)u)=0


We calculate terms in parentheses: -(-2(u-1)u), so:

-2(u-1)u

We multiply parentheses

-2u^2+2u

Back to the equation:

-(-2u^2+2u)


We get rid of parentheses

2u^2-2u=0

a = 2; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·2·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*2}=\frac{0}{4}
=0
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*2}=\frac{4}{4}
=1
$