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0=-3.9t^2+15.6t
We move all terms to the left:
0-(-3.9t^2+15.6t)=0
We add all the numbers together, and all the variables
-(-3.9t^2+15.6t)=0
We get rid of parentheses
3.9t^2-15.6t=0
a = 3.9; b = -15.6; c = 0;
Δ = b2-4ac
Δ = -15.62-4·3.9·0
Δ = 243.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15.6)-\sqrt{243.36}}{2*3.9}=\frac{15.6-\sqrt{243.36}}{7.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15.6)+\sqrt{243.36}}{2*3.9}=\frac{15.6+\sqrt{243.36}}{7.8} $
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