0=-6x(2x+7)

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Solution for 0=-6x(2x+7) equation: 



0=-6x(2x+7)

We move all terms to the left:

0-(-6x(2x+7))=0

We add all the numbers together, and all the variables

-(-6x(2x+7))=0



We calculate terms in parentheses: -(-6x(2x+7)), so:

-6x(2x+7)

We multiply parentheses

-12x^2-42x

Back to the equation:

-(-12x^2-42x)



We get rid of parentheses

12x^2+42x=0

a = 12; b = 42; c = 0;
Δ = b2-4ac
Δ = 422-4·12·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-42}{2*12}=\frac{-84}{24}
=-3+1/2
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+42}{2*12}=\frac{0}{24}
=0
$

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