0=-6x(x+2)+7x2

Solution for 0=-6x(x+2)+7x2 equation:

0=-6x(x+2)+7x^2

We move all terms to the left:

0-(-6x(x+2)+7x^2)=0

We add all the numbers together, and all the variables

-(-6x(x+2)+7x^2)=0


We calculate terms in parentheses: -(-6x(x+2)+7x^2), so:

-6x(x+2)+7x^2

determiningTheFunctionDomain
7x^2-6x(x+2)

We multiply parentheses

7x^2-6x^2-12x

We add all the numbers together, and all the variables

x^2-12x

Back to the equation:

-(x^2-12x)


We get rid of parentheses

-x^2+12x=0

We add all the numbers together, and all the variables

-1x^2+12x=0

a = -1; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-1)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-1}=\frac{-24}{-2}
=+12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-1}=\frac{0}{-2}
=0
$