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0=-6x(x-2x)
We move all terms to the left:
0-(-6x(x-2x))=0
We add all the numbers together, and all the variables
-(-6x(-1x))+0=0
We add all the numbers together, and all the variables
-(-6x(-1x))=0
We calculate terms in parentheses: -(-6x(-1x)), so:a = -6; b = 0; c = 0;
-6x(-1x)
We multiply parentheses
6x^2
Back to the equation:
-(6x^2)
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-12}=0$
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