0=-6x2+105

Solution for 0=-6x2+105 equation:

0=-6x^2+105

We move all terms to the left:

0-(-6x^2+105)=0

We add all the numbers together, and all the variables

-(-6x^2+105)=0

We get rid of parentheses

6x^2-105=0

a = 6; b = 0; c = -105;
Δ = b2-4ac
Δ = 02-4·6·(-105)
Δ = 2520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2520}=\sqrt{36*70}=\sqrt{36}*\sqrt{70}=6\sqrt{70}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{70}}{2*6}=\frac{0-6\sqrt{70}}{12}
=-\frac{6\sqrt{70}}{12}
=-\frac{\sqrt{70}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{70}}{2*6}=\frac{0+6\sqrt{70}}{12}
=\frac{6\sqrt{70}}{12}
=\frac{\sqrt{70}}{2}
$