0=-8x(x+6)

Solution for 0=-8x(x+6) equation:

0=-8x(x+6)

We move all terms to the left:

0-(-8x(x+6))=0

We add all the numbers together, and all the variables

-(-8x(x+6))=0


We calculate terms in parentheses: -(-8x(x+6)), so:

-8x(x+6)

We multiply parentheses

-8x^2-48x

Back to the equation:

-(-8x^2-48x)


We get rid of parentheses

8x^2+48x=0

a = 8; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·8·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*8}=\frac{-96}{16}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*8}=\frac{0}{16}
=0
$