0=0.03x2+0.6x-6

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Solution for 0=0.03x2+0.6x-6 equation:



0=0.03x^2+0.6x-6
We move all terms to the left:
0-(0.03x^2+0.6x-6)=0
We add all the numbers together, and all the variables
-(0.03x^2+0.6x-6)=0
We get rid of parentheses
-0.03x^2-0.6x+6=0
a = -0.03; b = -0.6; c = +6;
Δ = b2-4ac
Δ = -0.62-4·(-0.03)·6
Δ = 1.08
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.6)-\sqrt{1.08}}{2*-0.03}=\frac{0.6-\sqrt{1.08}}{-0.06} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.6)+\sqrt{1.08}}{2*-0.03}=\frac{0.6+\sqrt{1.08}}{-0.06} $

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