0=0.25x(x-5.7)

Solution for 0=0.25x(x-5.7) equation:

0=0.25x(x-5.7)

We move all terms to the left:

0-(0.25x(x-5.7))=0

We add all the numbers together, and all the variables

-(0.25x(x-5.7))=0


We calculate terms in parentheses: -(0.25x(x-5.7)), so:

0.25x(x-5.7)

We multiply parentheses

0x^2-0x

We add all the numbers together, and all the variables

x^2-1x

Back to the equation:

-(x^2-1x)


We get rid of parentheses

-x^2+1x=0

We add all the numbers together, and all the variables

-1x^2+x=0

a = -1; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-1)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-1}=\frac{-2}{-2}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-1}=\frac{0}{-2}
=0
$