0=1/3x12-4

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Solution for 0=1/3x12-4 equation: 


x in (-oo:+oo)

0 = (1/3)*x^12-4 // - (1/3)*x^12-4

0-((1/3)*x^12)+4 = 0

(-1/3)*x^12+0+4 = 0

-1/3*x^12 = -4 // : -1/3

x^12 = 12

x^12 = 12 // ^ 1/12

abs(x) = 12^(1/12)

x = 12^(1/12) or x = -12^(1/12)

x in { 12^(1/12), -12^(1/12) }

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