0=10(2)+(-3x)+(-4)+2(-2)+2(1)

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Solution for 0=10(2)+(-3x)+(-4)+2(-2)+2(1) equation: 



0=10(2)+(-3x)+(-4)+2(-2)+2(1)

We move all terms to the left:

0-(10(2)+(-3x)+(-4)+2(-2)+2(1))=0

We add all the numbers together, and all the variables

-(102+(-3x)+(-4)+2(-2)+21)=0



We calculate terms in parentheses: -(102+(-3x)+(-4)+2(-2)+21), so:

102+(-3x)+(-4)+2(-2)+21

determiningTheFunctionDomain
(-3x)+102+21+(-4)+2(-2)

We add all the numbers together, and all the variables

(-3x)+115

We get rid of parentheses

-3x+115

Back to the equation:

-(-3x+115)



We get rid of parentheses

3x-115=0

We move all terms containing x to the left, all other terms to the right

3x=115

x=115/3

x=38+1/3

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