0=12(2y-3)-3(6+5y)+3(y+2)

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Solution for 0=12(2y-3)-3(6+5y)+3(y+2) equation:


Simplifying
0 = 12(2y + -3) + -3(6 + 5y) + 3(y + 2)

Reorder the terms:
0 = 12(-3 + 2y) + -3(6 + 5y) + 3(y + 2)
0 = (-3 * 12 + 2y * 12) + -3(6 + 5y) + 3(y + 2)
0 = (-36 + 24y) + -3(6 + 5y) + 3(y + 2)
0 = -36 + 24y + (6 * -3 + 5y * -3) + 3(y + 2)
0 = -36 + 24y + (-18 + -15y) + 3(y + 2)

Reorder the terms:
0 = -36 + 24y + -18 + -15y + 3(2 + y)
0 = -36 + 24y + -18 + -15y + (2 * 3 + y * 3)
0 = -36 + 24y + -18 + -15y + (6 + 3y)

Reorder the terms:
0 = -36 + -18 + 6 + 24y + -15y + 3y

Combine like terms: -36 + -18 = -54
0 = -54 + 6 + 24y + -15y + 3y

Combine like terms: -54 + 6 = -48
0 = -48 + 24y + -15y + 3y

Combine like terms: 24y + -15y = 9y
0 = -48 + 9y + 3y

Combine like terms: 9y + 3y = 12y
0 = -48 + 12y

Solving
0 = -48 + 12y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-12y' to each side of the equation.
0 + -12y = -48 + 12y + -12y
Remove the zero:
-12y = -48 + 12y + -12y

Combine like terms: 12y + -12y = 0
-12y = -48 + 0
-12y = -48

Divide each side by '-12'.
y = 4

Simplifying
y = 4

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