0=12(x+1)+6x-48

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Solution for 0=12(x+1)+6x-48 equation: 



0=12(x+1)+6x-48

We move all terms to the left:

0-(12(x+1)+6x-48)=0

We add all the numbers together, and all the variables

-(12(x+1)+6x-48)=0



We calculate terms in parentheses: -(12(x+1)+6x-48), so:

12(x+1)+6x-48

We add all the numbers together, and all the variables

6x+12(x+1)-48

We multiply parentheses

6x+12x+12-48

We add all the numbers together, and all the variables

18x-36

Back to the equation:

-(18x-36)



We get rid of parentheses

-18x+36=0

We move all terms containing x to the left, all other terms to the right

-18x=-36

x=-36/-18

x=+2

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