0=12t2-4t+3

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Solution for 0=12t2-4t+3 equation: 



0=12t^2-4t+3

We move all terms to the left:

0-(12t^2-4t+3)=0

We add all the numbers together, and all the variables

-(12t^2-4t+3)=0

We get rid of parentheses

-12t^2+4t-3=0

a = -12; b = 4; c = -3;
Δ = b2-4ac
Δ = 42-4·(-12)·(-3)
Δ = -128
Delta is less than zero, so there is no solution for the equation

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