0=12x2-156x+360

Solution for 0=12x2-156x+360 equation:

0=12x^2-156x+360

We move all terms to the left:

0-(12x^2-156x+360)=0

We add all the numbers together, and all the variables

-(12x^2-156x+360)=0

We get rid of parentheses

-12x^2+156x-360=0

a = -12; b = 156; c = -360;
Δ = b2-4ac
Δ = 1562-4·(-12)·(-360)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(156)-84}{2*-12}=\frac{-240}{-24}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(156)+84}{2*-12}=\frac{-72}{-24}
=+3
$