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0=150+0V-16V^2
We move all terms to the left:
0-(150+0V-16V^2)=0
We add all the numbers together, and all the variables
-(150+0V-16V^2)=0
We get rid of parentheses
16V^2-0V-150=0
We add all the numbers together, and all the variables
16V^2-1V-150=0
a = 16; b = -1; c = -150;
Δ = b2-4ac
Δ = -12-4·16·(-150)
Δ = 9601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{9601}}{2*16}=\frac{1-\sqrt{9601}}{32} $$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{9601}}{2*16}=\frac{1+\sqrt{9601}}{32} $
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