0=16t(25-t)

Solution for 0=16t(25-t) equation:

0=16t(25-t)

We move all terms to the left:

0-(16t(25-t))=0

We add all the numbers together, and all the variables

-(16t(-1t+25))+0=0

We add all the numbers together, and all the variables

-(16t(-1t+25))=0


We calculate terms in parentheses: -(16t(-1t+25)), so:

16t(-1t+25)

We multiply parentheses

-16t^2+400t

Back to the equation:

-(-16t^2+400t)


We get rid of parentheses

16t^2-400t=0

a = 16; b = -400; c = 0;
Δ = b2-4ac
Δ = -4002-4·16·0
Δ = 160000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{160000}=400$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-400)-400}{2*16}=\frac{0}{32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-400)+400}{2*16}=\frac{800}{32}
=25
$