0=2(8-x)(5x+2)

Solution for 0=2(8-x)(5x+2) equation:

0=2(8-x)(5x+2)

We move all terms to the left:

0-(2(8-x)(5x+2))=0

We add all the numbers together, and all the variables

-(2(-1x+8)(5x+2))+0=0

We add all the numbers together, and all the variables

-(2(-1x+8)(5x+2))=0

We multiply parentheses ..

-(2(-5x^2-2x+40x+16))=0


We calculate terms in parentheses: -(2(-5x^2-2x+40x+16)), so:

2(-5x^2-2x+40x+16)

We multiply parentheses

-10x^2-4x+80x+32

We add all the numbers together, and all the variables

-10x^2+76x+32

Back to the equation:

-(-10x^2+76x+32)


We get rid of parentheses

10x^2-76x-32=0

a = 10; b = -76; c = -32;
Δ = b2-4ac
Δ = -762-4·10·(-32)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-84}{2*10}=\frac{-8}{20}
=-2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+84}{2*10}=\frac{160}{20}
=8
$