0=2(b-2)-3(3b+1)

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Solution for 0=2(b-2)-3(3b+1) equation:


Simplifying
0 = 2(b + -2) + -3(3b + 1)

Reorder the terms:
0 = 2(-2 + b) + -3(3b + 1)
0 = (-2 * 2 + b * 2) + -3(3b + 1)
0 = (-4 + 2b) + -3(3b + 1)

Reorder the terms:
0 = -4 + 2b + -3(1 + 3b)
0 = -4 + 2b + (1 * -3 + 3b * -3)
0 = -4 + 2b + (-3 + -9b)

Reorder the terms:
0 = -4 + -3 + 2b + -9b

Combine like terms: -4 + -3 = -7
0 = -7 + 2b + -9b

Combine like terms: 2b + -9b = -7b
0 = -7 + -7b

Solving
0 = -7 + -7b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '7b' to each side of the equation.
0 + 7b = -7 + -7b + 7b
Remove the zero:
7b = -7 + -7b + 7b

Combine like terms: -7b + 7b = 0
7b = -7 + 0
7b = -7

Divide each side by '7'.
b = -1

Simplifying
b = -1

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