0=2(t-6)+8+4(t-7)

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Solution for 0=2(t-6)+8+4(t-7) equation: 



0=2(t-6)+8+4(t-7)

We move all terms to the left:

0-(2(t-6)+8+4(t-7))=0

We add all the numbers together, and all the variables

-(2(t-6)+8+4(t-7))=0



We calculate terms in parentheses: -(2(t-6)+8+4(t-7)), so:

2(t-6)+8+4(t-7)

determiningTheFunctionDomain
2(t-6)+4(t-7)+8

We multiply parentheses

2t+4t-12-28+8

We add all the numbers together, and all the variables

6t-32

Back to the equation:

-(6t-32)



We get rid of parentheses

-6t+32=0

We move all terms containing t to the left, all other terms to the right

-6t=-32

t=-32/-6

t=5+1/3

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