0=2(x+5)(x-6)

Solution for 0=2(x+5)(x-6) equation:

0=2(x+5)(x-6)

We move all terms to the left:

0-(2(x+5)(x-6))=0

We add all the numbers together, and all the variables

-(2(x+5)(x-6))=0

We multiply parentheses ..

-(2(+x^2-6x+5x-30))=0


We calculate terms in parentheses: -(2(+x^2-6x+5x-30)), so:

2(+x^2-6x+5x-30)

We multiply parentheses

2x^2-12x+10x-60

We add all the numbers together, and all the variables

2x^2-2x-60

Back to the equation:

-(2x^2-2x-60)


We get rid of parentheses

-2x^2+2x+60=0

a = -2; b = 2; c = +60;
Δ = b2-4ac
Δ = 22-4·(-2)·60
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-22}{2*-2}=\frac{-24}{-4}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+22}{2*-2}=\frac{20}{-4}
=-5
$