0=2(x-4)(x+4)

Solution for 0=2(x-4)(x+4) equation:

Simplifying
0 = 2(x + -4)(x + 4)

Reorder the terms:
0 = 2(-4 + x)(x + 4)

Reorder the terms:
0 = 2(-4 + x)(4 + x)

Multiply (-4 + x) * (4 + x)
0 = 2(-4(4 + x) + x(4 + x))
0 = 2((4 * -4 + x * -4) + x(4 + x))
0 = 2((-16 + -4x) + x(4 + x))
0 = 2(-16 + -4x + (4 * x + x * x))
0 = 2(-16 + -4x + (4x + x2))

Combine like terms: -4x + 4x = 0
0 = 2(-16 + 0 + x2)
0 = 2(-16 + x2)
0 = (-16 * 2 + x2 * 2)
0 = (-32 + 2x2)

Solving
0 = -32 + 2x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x2' to each side of the equation.
0 + -2x2 = -32 + 2x2 + -2x2
Remove the zero:
-2x2 = -32 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-2x2 = -32 + 0
-2x2 = -32

Divide each side by '-2'.
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}