0=2(y+1)-5(y-5)

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Solution for 0=2(y+1)-5(y-5) equation: 



0=2(y+1)-5(y-5)

We move all terms to the left:

0-(2(y+1)-5(y-5))=0

We add all the numbers together, and all the variables

-(2(y+1)-5(y-5))=0



We calculate terms in parentheses: -(2(y+1)-5(y-5)), so:

2(y+1)-5(y-5)

We multiply parentheses

2y-5y+2+25

We add all the numbers together, and all the variables

-3y+27

Back to the equation:

-(-3y+27)



We get rid of parentheses

3y-27=0

We move all terms containing y to the left, all other terms to the right

3y=27

y=27/3

y=9

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