0=2.2-b2+7

Solution for 0=2.2-b2+7 equation:

0=2.2-b2+7

We move all terms to the left:

0-(2.2-b2+7)=0

We add all the numbers together, and all the variables

-(-1b^2+2.2+7)+0=0

We add all the numbers together, and all the variables

-(-1b^2+2.2+7)=0

We get rid of parentheses

1b^2-2.2-7=0

We add all the numbers together, and all the variables

b^2-9.2=0

a = 1; b = 0; c = -9.2;
Δ = b2-4ac
Δ = 02-4·1·(-9.2)
Δ = 36.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{36.8}}{2*1}=\frac{0-\sqrt{36.8}}{2}
=-\frac{\sqrt{}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{36.8}}{2*1}=\frac{0+\sqrt{36.8}}{2}
=\frac{\sqrt{}}{2}
$