0=23+2ab+3c-(c+2ba)

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Solution for 0=23+2ab+3c-(c+2ba) equation:


Simplifying
0 = 23 + 2ab + 3c + -1(c + 2ba)

Reorder the terms:
0 = 23 + 2ab + 3c + -1(2ab + c)
0 = 23 + 2ab + 3c + (2ab * -1 + c * -1)
0 = 23 + 2ab + 3c + (-2ab + -1c)

Reorder the terms:
0 = 23 + 2ab + -2ab + 3c + -1c

Combine like terms: 2ab + -2ab = 0
0 = 23 + 0 + 3c + -1c
0 = 23 + 3c + -1c

Combine like terms: 3c + -1c = 2c
0 = 23 + 2c

Solving
0 = 23 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
0 + -2c = 23 + 2c + -2c
Remove the zero:
-2c = 23 + 2c + -2c

Combine like terms: 2c + -2c = 0
-2c = 23 + 0
-2c = 23

Divide each side by '-2'.
c = -11.5

Simplifying
c = -11.5

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