0=27+u-4(3+u)

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Solution for 0=27+u-4(3+u) equation: 



0=27+u-4(3+u)

We move all terms to the left:

0-(27+u-4(3+u))=0

We add all the numbers together, and all the variables

-(27+u-4(u+3))+0=0

We add all the numbers together, and all the variables

-(27+u-4(u+3))=0



We calculate terms in parentheses: -(27+u-4(u+3)), so:

27+u-4(u+3)

determiningTheFunctionDomain
u-4(u+3)+27

We multiply parentheses

u-4u-12+27

We add all the numbers together, and all the variables

-3u+15

Back to the equation:

-(-3u+15)



We get rid of parentheses

3u-15=0

We move all terms containing u to the left, all other terms to the right

3u=15

u=15/3

u=5

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