0=280ln(a+1)+1925

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Solution for 0=280ln(a+1)+1925 equation:


Simplifying
0 = 280ln(a + 1) + 1925

Reorder the terms:
0 = 280ln(1 + a) + 1925
0 = (1 * 280ln + a * 280ln) + 1925

Reorder the terms:
0 = (280aln + 280ln) + 1925
0 = (280aln + 280ln) + 1925

Reorder the terms:
0 = 1925 + 280aln + 280ln

Solving
0 = 1925 + 280aln + 280ln

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-280aln' to each side of the equation.
0 + -280aln = 1925 + 280aln + -280aln + 280ln
Remove the zero:
-280aln = 1925 + 280aln + -280aln + 280ln

Combine like terms: 280aln + -280aln = 0
-280aln = 1925 + 0 + 280ln
-280aln = 1925 + 280ln

Divide each side by '-280ln'.
a = -6.875l-1n-1 + -1

Simplifying
a = -6.875l-1n-1 + -1

Reorder the terms:
a = -1 + -6.875l-1n-1

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