0=2cos(2x)-3sin(3x)

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Solution for 0=2cos(2x)-3sin(3x) equation:


Simplifying
0 = 2cos(2x) + -3sin(3x)

Remove parenthesis around (2x)
0 = 2cos * 2x + -3sin(3x)

Reorder the terms for easier multiplication:
0 = 2 * 2cos * x + -3sin(3x)

Multiply 2 * 2
0 = 4cos * x + -3sin(3x)

Multiply cos * x
0 = 4cosx + -3sin(3x)

Remove parenthesis around (3x)
0 = 4cosx + -3ins * 3x

Reorder the terms for easier multiplication:
0 = 4cosx + -3 * 3ins * x

Multiply -3 * 3
0 = 4cosx + -9ins * x

Multiply ins * x
0 = 4cosx + -9insx

Solving
0 = 4cosx + -9insx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4cosx' to each side of the equation.
0 + -4cosx = 4cosx + -4cosx + -9insx
Remove the zero:
-4cosx = 4cosx + -4cosx + -9insx

Combine like terms: 4cosx + -4cosx = 0
-4cosx = 0 + -9insx
-4cosx = -9insx

Divide each side by '-4osx'.
c = 2.25ino-1

Simplifying
c = 2.25ino-1

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