0=2k+1-(k-5)+20

Solution for 0=2k+1-(k-5)+20 equation:

0=2k+1-(k-5)+20

We move all terms to the left:

0-(2k+1-(k-5)+20)=0

We add all the numbers together, and all the variables

-(2k+1-(k-5)+20)=0


We calculate terms in parentheses: -(2k+1-(k-5)+20), so:

2k+1-(k-5)+20

determiningTheFunctionDomain
2k-(k-5)+1+20

We add all the numbers together, and all the variables

2k-(k-5)+21

We get rid of parentheses

2k-k+5+21

We add all the numbers together, and all the variables

k+26

Back to the equation:

-(k+26)


We get rid of parentheses

-k-26=0

We add all the numbers together, and all the variables

-1k-26=0

We move all terms containing k to the left, all other terms to the right

-k=26

k=26/-1

k=-26