0=2t(t-6)

Solution for 0=2t(t-6) equation:

0=2t(t-6)

We move all terms to the left:

0-(2t(t-6))=0

We add all the numbers together, and all the variables

-(2t(t-6))=0


We calculate terms in parentheses: -(2t(t-6)), so:

2t(t-6)

We multiply parentheses

2t^2-12t

Back to the equation:

-(2t^2-12t)


We get rid of parentheses

-2t^2+12t=0

a = -2; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-2)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-2}=\frac{-24}{-4}
=+6
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-2}=\frac{0}{-4}
=0
$