0=2x(0.01x+1)

Solution for 0=2x(0.01x+1) equation:

0=2x(0.01x+1)

We move all terms to the left:

0-(2x(0.01x+1))=0

We add all the numbers together, and all the variables

-(2x(0.01x+1))=0


We calculate terms in parentheses: -(2x(0.01x+1)), so:

2x(0.01x+1)

We multiply parentheses

0x^2+2x

We add all the numbers together, and all the variables

x^2+2x

Back to the equation:

-(x^2+2x)


We get rid of parentheses

-x^2-2x=0

We add all the numbers together, and all the variables

-1x^2-2x=0

a = -1; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-1)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-1}=\frac{0}{-2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-1}=\frac{4}{-2}
=-2
$