0=2x2+10x-16

Solution for 0=2x2+10x-16 equation:

0=2x^2+10x-16

We move all terms to the left:

0-(2x^2+10x-16)=0

We add all the numbers together, and all the variables

-(2x^2+10x-16)=0

We get rid of parentheses

-2x^2-10x+16=0

a = -2; b = -10; c = +16;
Δ = b2-4ac
Δ = -102-4·(-2)·16
Δ = 228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{57}}{2*-2}=\frac{10-2\sqrt{57}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{57}}{2*-2}=\frac{10+2\sqrt{57}}{-4}
$