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0=2x^2+13x-24
We move all terms to the left:
0-(2x^2+13x-24)=0
We add all the numbers together, and all the variables
-(2x^2+13x-24)=0
We get rid of parentheses
-2x^2-13x+24=0
a = -2; b = -13; c = +24;
Δ = b2-4ac
Δ = -132-4·(-2)·24
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-19}{2*-2}=\frac{-6}{-4} =1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+19}{2*-2}=\frac{32}{-4} =-8 $
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