0=2x2-23x-39

Solution for 0=2x2-23x-39 equation:

0=2x^2-23x-39

We move all terms to the left:

0-(2x^2-23x-39)=0

We add all the numbers together, and all the variables

-(2x^2-23x-39)=0

We get rid of parentheses

-2x^2+23x+39=0

a = -2; b = 23; c = +39;
Δ = b2-4ac
Δ = 232-4·(-2)·39
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-29}{2*-2}=\frac{-52}{-4}
=+13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+29}{2*-2}=\frac{6}{-4}
=-1+1/2
$