0=2x2-8x+8

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Solution for 0=2x2-8x+8 equation: 



0=2x^2-8x+8

We move all terms to the left:

0-(2x^2-8x+8)=0

We add all the numbers together, and all the variables

-(2x^2-8x+8)=0

We get rid of parentheses

-2x^2+8x-8=0

a = -2; b = 8; c = -8;
Δ = b2-4ac
Δ = 82-4·(-2)·(-8)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-8}{-4}=+2$

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