0=3(2x-5)-5(4x+x)

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Solution for 0=3(2x-5)-5(4x+x) equation: 



0=3(2x-5)-5(4x+x)

We move all terms to the left:

0-(3(2x-5)-5(4x+x))=0

We add all the numbers together, and all the variables

-(3(2x-5)-5(+5x))+0=0

We add all the numbers together, and all the variables

-(3(2x-5)-5(+5x))=0



We calculate terms in parentheses: -(3(2x-5)-5(+5x)), so:

3(2x-5)-5(+5x)

We multiply parentheses

6x-25x-15

We add all the numbers together, and all the variables

-19x-15

Back to the equation:

-(-19x-15)



We get rid of parentheses

19x+15=0

We move all terms containing x to the left, all other terms to the right

19x=-15

x=-15/19

x=-15/19

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