0=3(5x+2)-(x+2)2

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Solution for 0=3(5x+2)-(x+2)2 equation: 



0=3(5x+2)-(x+2)2

We move all terms to the left:

0-(3(5x+2)-(x+2)2)=0

We add all the numbers together, and all the variables

-(3(5x+2)-(x+2)2)=0



We calculate terms in parentheses: -(3(5x+2)-(x+2)2), so:

3(5x+2)-(x+2)2

We multiply parentheses

15x-2x+6-4

We add all the numbers together, and all the variables

13x+2

Back to the equation:

-(13x+2)



We get rid of parentheses

-13x-2=0

We move all terms containing x to the left, all other terms to the right

-13x=2

x=2/-13

x=-2/13

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