0=3(a-5)-2(2a+1)

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Solution for 0=3(a-5)-2(2a+1) equation: 



0=3(a-5)-2(2a+1)

We move all terms to the left:

0-(3(a-5)-2(2a+1))=0

We add all the numbers together, and all the variables

-(3(a-5)-2(2a+1))=0



We calculate terms in parentheses: -(3(a-5)-2(2a+1)), so:

3(a-5)-2(2a+1)

We multiply parentheses

3a-4a-15-2

We add all the numbers together, and all the variables

-1a-17

Back to the equation:

-(-1a-17)



We get rid of parentheses

1a+17=0

We add all the numbers together, and all the variables

a+17=0

We move all terms containing a to the left, all other terms to the right

a=-17

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