0=3(y+1)-5(y-5)

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Solution for 0=3(y+1)-5(y-5) equation: 



0=3(y+1)-5(y-5)

We move all terms to the left:

0-(3(y+1)-5(y-5))=0

We add all the numbers together, and all the variables

-(3(y+1)-5(y-5))=0



We calculate terms in parentheses: -(3(y+1)-5(y-5)), so:

3(y+1)-5(y-5)

We multiply parentheses

3y-5y+3+25

We add all the numbers together, and all the variables

-2y+28

Back to the equation:

-(-2y+28)



We get rid of parentheses

2y-28=0

We move all terms containing y to the left, all other terms to the right

2y=28

y=28/2

y=14

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